Need help with the steps The answers Check the design shown

(Need help with the steps) The answers:

Check the design shown in Figure 1. Assume A36 steel and the SMAW welding process. Check for it OK? failure of the member as well as the weld. Is the design satisfactory? If not, what should be done to make 1/4 t-1/2\" Po= 62 kips | | 6\" Figure 1

Solution

Let us determine the strength of weld

total weld length = 5+5+6=16 in

weld size provided = 1/4

D=4

Weld strength = 1.392*4*16=89.1 kips

Demand/capacity = 62/89.1=0.70

Block shear check of 3/8\" plate:

Area of plate in shear =A_v= (5+5)*3/8=3.75 in²

Area of plate in tension =A_t= 6*3/8=2.25 in²

F_y=36 ksi

F_u=58 ksi

0.6*F_u*A_v + F_u*A_t = 0.6*58*3.75 + 58*2.25=261 kips

0.6*F_y*A_v+F_u*A_t=0.6*36*3.75 + 58*2.25=211.5 kips

Block shear strength = 0.75*min(261,211.5)=158.625 kips

D/C = 62/158.625=0.4

gross section yielding tension capacity of 3/8 thick plate = 6*3/8 * 36*0.9 = 72.9 kips

D/C=62/72.9=0.85