Consider a home that uses the equivalent of 16000 kWh per ye
Consider a home that uses the equivalent of 16,000 kWh per year for the following energy loads.
Domestic hot water: 3,500 kWh
Refrigeration: 1,300 kWh
Lighting: 1,500 kWh
Heating: 4,800 kWh
Cooling: 2,400 kWh
Make this house a net zero home.
Solution
to make this house net zero home
the percentage increase of each load=(16000-(3500+1300+1500+4800+2400))/(3500+1300+1500+4800+2400)*100=18.52
the domestic hot water load increased to =3500+0.1852*3500=4148.148 KWh
the refrigeration load increased to =1300+0.1852*1300=1540.76 KWh
the lighting load increased to =1500+0.1852*1500=1777.8 KWh
the heating load increased to =4800+0.1852*4800=5688.96 KWh
the cooling load increased to =2400+0.1852*2400=2844.48 KWh
