Homework SourseA particle moves in a circular path of 04m radius Calculate
A particle moves in a circular path of 0.4m radius. Calculate the magnitude a of the acceleration of the particle. If its speed is constant at 0.6m/s. If its speed is 0.6m/s but is increasing at the rate of 1.2m/s each second.
Solution
Tangential speed v = r*w...........where w is the angular velocity
0.6 = 0.4*w
w = 1.5 rad/s
a)
Tangential acceleration, at = 0
Normal acceleration, an = rw2
= 0.4 * 1.52
an = 0.9 m/s2
Magnitude of total acceleration a = sqrt (at2 + an2)
= sqrt (0 + 0.92)
= 0.9 m/s2
b)
Tangential acceleration, at = 1.2 m/s2
Normal acceleration, an = rw2
= 0.4 * 1.52
an = 0.9 m/s2
Magnitude of total acceleration a = sqrt (at2 + an2)
= sqrt (1.22 + 0.92)
= 1.5 m/s2
