A heat pump absorbs heat energy from the outside air and sup

A heat pump absorbs heat energy from the outside air and supplies heat energy to a building at a rate of 16,000 kJ/h. If the heat pump comsumes energy at a rate of 3 kW, what is the COP of the heat pump?

Solution

heat effecting = 16000 kJ/h

                       = 16000/3600

                       = 4.44kW

heat pump power = 3kW

COP = heating effecting /heat pump power

         = 4.44/3

         = 1.48