y6x10 yx22 solve the following system of equation algebraica

y=-6x-10

y=x^2-2

solve the following system of equation algebraically

given equations

y=-6x-10

y=x^2-2

there are two y equations given , equate them

6x-10 = x^2 -2

x^2 -2 -6x +10=0

x^2 -6x +8=0

x^2 -2x-4x+8=0

x(x-2)-4(x-2) =0

(x-2) (x-4)=0

so (x-2) =0 or (x-4)=0

x=2 or x=4

y value when x =2, y=2

y value when x=4 ,y =14

small value of x =2

large value of x=4