N2n31SolutionAs n increases n2 1 n3 is approximately equa


N^2/n^3+1

Solution

As n increases ( n2 / 1+ n3 ) is approximately equal to n2 / n3 ( = 1/ n ) as n3 > >1

and we know that (1/n) , which is harmonic series sum is divergent

Therefore , n=1 (n2 / 1+ n3 ) is also divergent

 N^2/n^3+1SolutionAs n increases ( n2 / 1+ n3 ) is approximately equal to n2 / n3 ( = 1/ n ) as n3 > >1 and we know that (1/n) , which is harmonic series

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