N2n31SolutionAs n increases n2 1 n3 is approximately equa
Solution
As n increases ( n2 / 1+ n3 ) is approximately equal to n2 / n3 ( = 1/ n ) as n3 > >1
and we know that (1/n) , which is harmonic series sum is divergent
Therefore , n=1 (n2 / 1+ n3 ) is also divergent
