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tp/elearing 09 ketes cdu/ webappo/ sesment/takec/bunchyp courme anuesmemt earni Sol 010 ake/launchjsp?course assessment jid 1420253, 1&course; id- 493375185, 1acontent id- 1644614 16se QUESTION 16 A doctor claims that the standard deviation of systolic blood standard deviation of systolic blood pressure is 12 mmblg A random sample of 24 parierts found a standard deviation of 14 mmig Assune the vatiable s omalyued = 0 01, what are the critical X2 values? - A) 9.262 and 44 181 B) 13.091 and 35.172 o C) 13.848 and 36 415 O D) 11.524 and 44 314 pressure is 12 mmHg A random sample tt 24 patients fourd·strdirt de ition d\'aning AssumRe vaiabl·on-dili i A. 4- QUESTION 17 A lumber mill is tested for consistency by measuring the variance 0.006 square inches, is there e 4 points bard thickness The target accuracy is a variance of 0 0035 square inches or less. If 24 measurements are made and thv of board hickness The taget accuracy is a variance of A) No, since the X2 test value 39 43 is less than the critical value 41 638 B ) Yes, since the X2 test value 8 22 is less than the citical value 41 638 - C) No, since the X2 test value 39 43 is less than the citical value 42 980 D) Yes, since the X2 test value 8 22 is less than the cmcal value 42 900 i points QUESTION 18 150 ata-ogg would

Solution

16.

As alpha = 0.01, and df = n - 1 = 23, then the critical values, by table/technology, are

chi^2(crit) = 9.260424776 and 44.18127525 [ANSWER, A]

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17.

Formulating the null and alternative hypotheses,              
              
Ho:   sigma   <=   0.059160798  
Ha:    sigma   >   0.059160798  
              
As we can see, this is a    right   tailed test.      
              
Thus, getting the critical chi^2, as alpha =    0.01   ,      
alpha =    0.01          
df = N - 1 =    23          
chi^2 (crit) =    41.63839812        
              
Getting the test statistic, as              
s = sample standard deviation =    0.077459667          
sigmao = hypothesized standard deviation =    0.059160798          
n = sample size =    24          
              
              
Thus, chi^2 = (N - 1)(s/sigmao)^2 =    39.42857143          
              
As chi^2 < chi^2(crit), then we FAIL TO REJECT THE NULL HYPOTHESIS.              

Hence, it is OPTION C. [ANSWER]

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