Given the indicated parts of triangle ABC with 90 approxima

Given the indicated parts of triangle ABC with = 90°, approximate the remaining parts. (Round your answers for b and c to one decimal place.) = 61°30\', a = 20.1

Solution

= 90°, = 61°30\'

+ + =180°

+ 61°30\'+ 90°=180°

= 28°30\'

by law of sines a_/sin =b_/sin =c_/sin

_{20.1/sin28°30\'} =b_/sin61^o30\' =c_/sin90^o

20.1_/sin28°30\' =b_/sin61^o30\' =c_/1

20.1_/sin28°30\' =b_/sin61^o30\' =c

c=20.1_/sin28°30\'

c=42.1

b_/sin61^o30\'=20.1_/sin28°30\'

b=sin61^o30\' *20.1_/sin28°30\'

b=37.0

so b =37.0, c=42.1