Let p be x is cubed and let q be x3 is greater than x Write
Solution
A. The conditional statement : If P, then Q. - True
If x is cubed, then x3 is greater than x.
B. The converse : If Q, then P. - False
If x3 is greater than x, then x is cubed.
C. The inverse : If not P, then not Q. - False
If x3 is not greater than x, then x is not cubed.
D. The contrapositive : If not Q, then not P. - True
If x is not cubed, then x3 is not greater than x.
