Using the table of indices above compute the following a ind

Using the table of indices above, compute the following

a) ind₃28

b) ind₃5¹⁰

d) The least residue 7¹⁰ modulo 17

Solution

The second row should read ind ₃n (not ind 3n)

As ind is defined modulo 17

(a) ind 328 = ind 328 mod 17

                    =ind 5

                    =5

(b) Ind 3510 = Ind 3510 mod 17

                     = ind 8

                     =10

(c) From the table Ind(15.13) = ind 15+ind 13

                                               = 10

so the least residue =8

(d) ind(710) = ind (71) +ind(10)

                    = ind (3)+ ind(10)

                    =4

So the least residue 0f 710 =13