Please helpdetail explanation will be greatful Overall mean

Please help....detail explanation will be greatful!!

Overall mean: 22.78

Overall Std. Dev: 11.85

Test statistic: 0.6255

Critical Value, when alpha = 0.05: 3.68

c. Rank the data (1=lowest), using the average of the ranks for any set of tied observations. then find the Kruskal-Wallis statistic

then adjust the value of H by dividing it by

where t_i is the number of observations that are tied for a given set of ranks. Compare this test statistics with the critical value of chi-Square (with alpha =0.05), which has k-1 degrees of freedom to decide whether to accept or reject the null hypothesis.

Solution

So the Kruskal-Wallis statistic:

H=0.851756

So accept the null hypothesis.