Given the following graph Give the adjacency matrix for this
Solution
Please find the C++ program for the above
/* C++ program were the adjancy matrix in the list as the input*/
/* including the libaries files*/
#include<iostream> // std input and output files
#include<Stdio.h>
#inclue<conio.h>
using namespace std;
struct node // crestion of the structure with the name node
{
int from,to; //variable declaration in form of integer
} a[5] ,t; //global variable declaration
void addEdges(int am[][6],int i, int in, int j) // adding the edges, along witht eh variable declarations
{
a[in].from = i //getting the value from i
a[in].to = j //moving the value to j
for(int r=0;r<=in ; r++) //creation of the nested for loop
{
for ( intp=r+;p<=in;p++)
{
if (a[r].from >a[p].from)
{
t=a[r];
a[r] = a[p];
a[p] = t;
} //if loop is getting closed
else if (a[r].from == a[p].from)
{
if(a[r].to>a[p].to)
{
t=a[r];
a[r] = a[p];
a[p] = t;
}
}
else
{
continue;
}
}
}
}
}
}
int main () //this main class is getting created for vertices
{
/* varaible declaraion
int n,c=0 ,x,y,ch,i,j;
/* printing statement in the screen*/
cout <<\"enter the number of vertices \ \"; \\*\ means the new line*\\
cin >>n; /* getting the user inpuit*/
int am [5],[5]; /* delcaration of the array*/
for (int i=0;i<5;i++)
{
for (int j=0 ; j<5;j++)
{
am[i][j] =0;
}
}
/* using the while loop*/
while(ch != -1) /* ch is the varainle value is not equal to -1*/
{
/* printing statement in the screen*/
cout <<\"Enter the nodes between which edges need to be intorduced\ \";
/* input statement to recieve the input from the user*/
cin>>x>>y; /* both the value for x as well as y will be obtained.
addEdge (am,x,y,c);
c++;
cout<<\"press -1 to exit the screen \ \"; /* info in realte to exit is provided.
/* input statement will recieve the value given by the user
cin >>ch;
}
for (int j=0; j<c ; j++){
am[a[j].from[j] = 1; /* checking the value as equal to 1
am[a[j].to][j] =1
/* in above two statements the vetices from were to were the edges are provided will be shown clearly*/;
}
for (int i=0; i<n;i++)
{
for(int j=0; j<c;j++)
{
cout<am[i][j] <<\"\\t\";
}
\\cout<<end1;
}
getch(); /* function call statement untill the condition getting failes
}


