Homework Soursefinding a taylor series of cos2x centered at a pi2 I though
finding a taylor series of cos(2x) centered at a = pi/2 I thought I found the right formula but it doesn\'t seem to work for all values of x??
Solution
= f(/2) + (x-/2)f\'(/2) + (x-/2)^2f\"(/2)/2 + (x-/2)^3f\"\'(/2)/6 + .....
= -1 + (x-/2)*0 + (x-/2)^2*(4/2) + (x-/2)^3*(0) + ...
= -1 + 2(x-/2)^2 - (2/3)(x-/2)^4 + .....
formula = summation(n=0 to infinity) (-1)^(n+1) * ((x-/2)^2n) * (2^2n) * (1/(2n)!)
