The time until recharge for a battery in a laptop computer u
Solution
Normal Distribution
Mean ( u ) =260
Standard Deviation ( sd )=50
Normal Distribution = Z= X- u / sd ~ N(0,1)
1)
P(X > 240) = (240-260)/50
= -20/50 = -0.4
= P ( Z >-0.4) From Standard Normal Table
= 0.6554
2)
25% is
P ( Z < x ) = 0.25
Value of z to the cumulative probability of 0.25 from normal table is -0.674
P( x-u/s.d < x - 260/50 ) = 0.25
That is, ( x - 260/50 ) = -0.67
--> x = -0.67 * 50 + 260 = 226.3
75% is
P ( Z < x ) = 0.75
Value of z to the cumulative probability of 0.75 from normal table is 0.674
P( x-u/s.d < x - 260/50 ) = 0.75
That is, ( x - 260/50 ) = 0.67
--> x = 0.67 * 50 + 260 = 293.7
3)
P ( Z > x ) = 0.95
Value of z to the cumulative probability of 0.95 from normal table is -1.64
P( x-u/ (s.d) > x - 260/50) = 0.95
That is, ( x - 260/50) = -1.64
--> x = -1.64 * 50+260 = 177.75
