Justify that the following circuit represents the functional
Solution
1) Sender, receiver, medium, message, and protocol.
2) Internet draft A working Internet document (a work in progress) with no official status and a six-month lifetime.
Proposed Standard: It was a standard developed by IETF as a less mature and well defined standard.
3) a. If one connection fails, the other connections will still be working.
b. The other devices will still be able to send data through the hub; there will be no
access to the device which has the failed connection to the hub.
c. All transmission stops.
d. The failed connection may disable the whole network unless it is a dual ring.
4) Application Layer: Packet
Network Layer: IP Datagram
DataLink Layer: Frame
5) Application Layer: sagarsetti4u@gmail.com
Network Layer:Logical Addresses
Data Link Layer: Link Layer Addresses
6) No, multiplexing/ de-multiplexing at transport layer does notmean combining several upper-layer packets (from the sameor different applications) into one transport-layer packet. Itonly means that each of the transport-layer protocols such asTCP can carry a packet from any application-layer protocolthat needs its service. However, a transport-layer packet cancarry one, and only one, packet from an application layerprotocol. For instance, UDP can carry a message from FTPin one user datagram and a message from HTTP in anotheruser datagram
7) a) Print your Boarding Pass and check in your Luggage.
b) Head to Security
c) Find your gate/terminal
d) Wait for Your Plane
e) Wait for Your Announcement
f) Get the Boarding pass checked
g) Enter the aircraft
h) Get Settled Down
We can Prove that it is a full adder by constructing Truth Table.
Initially Full adder Truth Table is given by
x
y
z
Sum
Carry
0
0
0
0
0
0
0
1
1
0
0
1
0
1
0
0
1
1
0
1
1
0
0
1
0
1
0
1
0
1
1
1
0
0
1
1
1
1
1
1
Now Let us See For (xy) Cin and For (xy) Cin+xy
x
y
Cin
(xy)
(xy) Cin
(xy) Cin
xy
(xy) Cin+xy
0
0
0
0
0
0
0
0
0
0
1
0
1
0
0
0
0
1
0
1
1
0
0
0
0
1
1
1
0
1
0
1
1
0
0
1
1
0
0
0
1
0
1
1
0
1
0
1
1
1
0
0
0
0
1
1
1
1
1
0
1
0
1
1
Hence we can see that (xy) Cin and Sum are identical.
(xy) Cin+xy and Carry are Identical.
Hence it a Full Adder
| x | y | z | Sum | Carry |
| 0 | 0 | 0 | 0 | 0 |
| 0 | 0 | 1 | 1 | 0 |
| 0 | 1 | 0 | 1 | 0 |
| 0 | 1 | 1 | 0 | 1 |
| 1 | 0 | 0 | 1 | 0 |
| 1 | 0 | 1 | 0 | 1 |
| 1 | 1 | 0 | 0 | 1 |
| 1 | 1 | 1 | 1 | 1 |




