To show that the point 35 45 is on the unit circle we need t

To show that the point (3/5, 4/5) is on the unit circle, we need to prove that (3/5)^2 + (4/5)^2 =. The distance between (2, -5) and (-7, -5) is The midpoint of the line segment that joins the given points is given by: (, ).

Solution

for unit circle x^2 + y^2=1

Therefore for point (3/5,4/5) on the unit circle,(3/5)^2 + (4/5)^2=1

the distance between points (2,-5) and (-7,-5)

We use distance formula which is

d=sqrt((x2 - x1)^2 +(y2-y1)^2)= sqrt((-7-2)^2 + (-5+5)^2)=sqrt(9^2)=9 units

midpoint of the given points (2,-5) and (-7,-5) is ((-7+2)/2,(-5-5)/2)= (-2.5,-5)