1 Using STATDISK Minitab EXCEL a TI 8384 PLUS calculator or

1. Using STATDISK, Minitab, EXCEL, a TI – 83/84 PLUS calculator, or some other suitable technology, randomly generate 100 post rates from a normally distributed population having a mean of 76.3 and a standard deviation of 12.5.

2. Repeat step 1 and generate a second sample of 100 values from a normally distributed population having a mean of 76.3 and a standard deviation of 12.5.

3. Generate a better sample of 100 values from a normally distributed population with a standard deviation of 12.5, but use a mean of 83.3 for this third sample.

4. What do you conclude from step for? Given the way that the three samples were generated, we know that they come from populations with means that are not all equal. If step four resulted in a failure to reject the NULL how about the sis, what type of error was made (type one or type two)? Explain how correct application of a sound statistical procedure can result in such an error.

DATA SET 1: APPENDIX B (COPY THE LINK)

http://wps.aw.com/aw_triola_biostatistics_1/41/10634/2722390.cw/index.html

(BIOSTATISTICS for the biological health sciences BOOK by TRIOLA)

Using the plus rates of females listed in dataset 1 in appendix B, we find that n = 40, \"\\bar{x}\" = 76.3, and S = 12.5. We will assume that the statistics are reasonable good estimates of the parameters for the population of all women. Conduct an experiment with the following steps:

1. Using STATDISK, Minitab, EXCEL, a TI – 83/84 PLUS calculator, or some other suitable technology, randomly generate 100 post rates from a normally distributed population having a mean of 76.3 and a standard deviation of 12.5.

2. Repeat step 1 and generate a second sample of 100 values from a normally distributed population having a mean of 76.3 and a standard deviation of 12.5.

3. Generate a better sample of 100 values from a normally distributed population with a standard deviation of 12.5, but use a mean of 83.3 for this third sample.

4. What do you conclude from step for? Given the way that the three samples were generated, we know that they come from populations with means that are not all equal. If step four resulted in a failure to reject the NULL how about the sis, what type of error was made (type one or type two)? Explain how correct application of a sound statistical procedure can result in such an error.

DATA SET 1: APPENDIX B (COPY THE LINK)

http://wps.aw.com/aw_triola_biostatistics_1/41/10634/2722390.cw/index.html

(BIOSTATISTICS for the biological health sciences BOOK by TRIOLA)

Solution

The R software will be used for simulation purpose.

1. Using the R function rnorm, we first simulate hundred observations.

2. The function in previous is repeated again.

3. The mean parameter is changed and a new object is created.

Note that the \"Step 4\" that is being referred at \"4. What do you conclude from step for? \" suggests that what is printed there as \"4. What do ...\" is \"Step 5\".

4. Applying anova and lm on the x1, x2, and x3, we get

Thus, we reject the null hypothesis that the three means are equal.

1. Using STATDISK, Minitab, EXCEL, a TI – 83/84 PLUS calculator, or some other suitable technology, randomly generate 100 post rates from a normally distributed

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