Find an elementary matrix E such that EAC where A 1 3 0 2 1
Solution
EA = C
A = 1 3 0
2 1 5
0 4 -2
C = 1 3 0
2 13 -1
0 4 -2
we have EA = C
we multiply both sides by A-1
E*A*A-1 = C*A-1
E = C*A-1 // A*A-1 = I
now we calculate A-1
A-1 = 11/5 -3/5 -3/2
-2/5 1/5 1/2
-4/5 2/5 1/2
now E = C*A-1
E = 1 0 0
0 1 3
0 0 1
![Find an elementary matrix E such that EA-C where A = [1 3 0 2 1 5 0 4 -2] and C = [1 2 0 2 13 -1 0 4 -2]SolutionEA = C A = 1 3 0 2 1 5 0 4 -2 C = 1 3 0 2 13 -1 Find an elementary matrix E such that EA-C where A = [1 3 0 2 1 5 0 4 -2] and C = [1 2 0 2 13 -1 0 4 -2]SolutionEA = C A = 1 3 0 2 1 5 0 4 -2 C = 1 3 0 2 13 -1](/WebImages/13/find-an-elementary-matrix-e-such-that-eac-where-a-1-3-0-2-1-1015961-1761524943-0.webp)