This data is heights for 50 men and 50 women You want to kno

This data is heights for 50 men and 50
women. You want to know if the genders
differ in height.

What test do you use?
Perform the test and present your results.

	HEIGHT (inches)
	Women	Men
	60	62
	72	67
	59	65
	62	69
	63	72
	61	75
	72	77
	69	68
	67	70
	68	71
	71	74
	57	69
	59	67
	61	72
	65	73
	63	71
	68	71
	66	70
	66	70
	67	63
	64	67
	62	69
	61	73
	66	70
	65	70
	69	69
	72	67
	70	65
	68	69
	68	72
	66	75
	67	77
	67	68
	65	70
	66	71
	67	74
	67	69
	64	67
	68	72
	63	73
	62	71
	68	71
	67	70
	69	70
	66	63
	66	67
	68	69
	83	73
	60	70
	64	70

This data is heights for 50 men and 50
women. You want to know if the genders
differ in height.

What test do you use?
Perform the test and present your results.

	HEIGHT (inches)
	Women	Men
	60	62
	72	67
	59	65
	62	69
	63	72
	61	75
	72	77
	69	68
	67	70
	68	71
	71	74
	57	69
	59	67
	61	72
	65	73
	63	71
	68	71
	66	70
	66	70
	67	63
	64	67
	62	69
	61	73
	66	70
	65	70
	69	69
	72	67
	70	65
	68	69
	68	72
	66	75
	67	77
	67	68
	65	70
	66	71
	67	74
	67	69
	64	67
	68	72
	63	73
	62	71
	68	71
	67	70
	69	70
	66	63
	66	67
	68	69
	83	73
	60	70
	64	70

HERE, WE USE THE 2-SAMPLE T TEST.

*******************
Let

group 1 = women
group 2 = men

Formulating the null and alternative hypotheses,

Ho:   u1 - u2   =   0
Ha:   u1 - u2   =/   0
At level of significance =    0.05
As we can see, this is a    two   tailed test.
Calculating the means of each group,

X1 =    65.88
X2 =    69.94

Calculating the standard deviations of each group,

s1 =    4.321942118
s2 =    3.253945799

Thus, the standard error of their difference is, by using sD = sqrt(s1^2/n1 + s2^2/n2):

n1 = sample size of group 1 =    50
n2 = sample size of group 2 =    50
Thus, df = n1 + n2 - 2 =    98
Also, sD =    0.765079694

Thus, the t statistic will be

t = [X1 - X2 - uD]/sD =    -5.30663672

where uD = hypothesized difference =    0

Now, the critical value for t is

tcrit =    +/-   1.984467455


Thus, comparing t and tcrit, we decide to   WE REJECT THE NULL HYPOTHESIS.

Also, using p values,

p =    0.000000694557

Comparing p < 0.05,    WE REJECT THE NULL HYPOTHESIS.

There is significant evidence at 0.05 level that there is a difference between the mean heights of men and women. [conclusion]

This data is heights for 50 men and 50 women. You want to know if the genders differ in height. What test do you use? Perform the test and present your results

This data is heights for 50 men and 50 women You want to kno

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