The equation is ux x5 7x3 4x 3 and the invrse is vx u1

The equation is u(x) = x⁵ + 7x³ + 4x + 3, and the invrse is v(x) = u^-1 (x), and the question is the find v\'(3). Did I do this correctly? Work shown in picture:

Solution

what you\'re doing this well , the answer is : \"1/4\" After deriving the original function , with the point you evaluate what you found (x=0) and give you 4, but as you ask the derivative of its inverse , which is 1/4