In a population of scores X 83 corresponds to z 050 and X
In a population of scores, X = 83 corresponds to z = –0.50 and X = 93 corresponds to z = +2.00. What are the values for the population mean and standard deviation?
a.
= 85 and = 4
b.
= 85 and = 2
c.
= 81 and = 4
d.
= 81 and = 6
| a. | = 85 and = 4 | ||
| b. | = 85 and = 2 | ||
| c. | = 81 and = 4 | ||
| d. | = 81 and = 6 |
Solution
As
x = u + z s
Then
83 = u - 0.50 s
93 = u + 2.00 s
Solving for u and s in this system,
u = 85
s = 4 [ANSWER, OPTION A]
