Determine the mass and the weight of the air contained in a

Determine the mass and the weight of the air contained in a room whose dimensions are 6m times 6m times 8m. Assume the density of the air is uniform and is 1.16 kg/m^3.

Solution

Solution :

We know that

Density = mass /volume

Given Density = 1.16 kg/m³

Volume = length*breadth*height= 6*6*8= 288 m³

Now Mass = Density *volume = 1.16*288= 334.08 Kg.

Weight = Mass*Gravity = 334.08*9.81 = 3277 N