Let zlnx2y2 where xsquarootst and yst use the chain rule to

Let z=ln(x^2+y^2) where x=squaroot(st) and y=s+t. use the chain rule to express ?z/?s and ?z/?t in terms of s and t.

Solution

z= ln(x2+y2)

x= sqrt(st)
dx/ds= 1/(2*(st))
dx/dt=1/(2*(st))
y= (s+t)
dy/ds=t
dy/dt=s

z= ln(st+ (s+t)^2)

dz/ds= (2s+3t)/((s+t)^2 + st)

dz/dt= (3s+2t)/((s+t)^2 + st)

Let z=ln(x^2+y^2) where x=squaroot(st) and y=s+t. use the chain rule to express ?z/?s and ?z/?t in terms of s and t. Solutionz= ln(x2+y2) x= sqrt(st) dx/ds= 1/(

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