A 150 g baseball had angular momentum 81 kgm2s about a verti

A 150 g baseball had angular momentum 8.1 kg·m²/s about a vertical axis throughg the batter. If it\'s moving at 50 m/s without spinning, by how much will it miss the batter\'s axis? Answer in meters.

Please show work if possible so I can practice, much thanks!

If the baseball is moving hoeizontally in a straight line, angular momentum about a vertical axis is

L = m v b

b = L / m v

= (8.1) / (150 * 10^-3 * 50)

= 1.08 m

$A 150 g baseball had angular momentum 8.1 kg·m2/s about a vertical axis throughg the batter. If it\'s moving at 50 m/s without spinning, by how much will it mis$

A 150 g baseball had angular momentum 81 kgm2s about a verti

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