A train running along a straight track at 48 ms is slowed un
A train running along a straight track at 48 m/s is slowed uniformly to a stop in 69 seconds. Find the stopping distance.
A train running along a straight track at 48 m/s is slowed uniformly to a stop in 69 seconds. Find the stopping distance.
Solution
It is slowing uniformly, it means that it has constant deaccleration of value a.
From equations of linear motion:
v = u -at
v= 0 = final velocity
u=48m/s
t=69
a = 48/69 m/s2
Stoppage distance S
v2 = u2 -2aS
S = u2/2a = (482)/(2*48/69) = 1656 meters
