A long jumper leaves the ground at an angle of 201 degree to

A long jumper leaves the ground at an angle of 20.1 degree to the horizontal and at a speed of 10.5 m/s. How far does he jump? The acceleration due to gravity is 9.8 m/s^2. Answer in units of m. What maximum height does he reach? Answer in units of m.

Solution

x = v² * sin (2theta) / g

= 10.5² * sin (2 * 20.1) / 9.8

x = 7.26 m

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H_max = v² * sin² theta / (2 g)

= 10.5² * sin² 20.1 / (2 * 9.8)

= 0.666 m