Look at the last page first ACTIVITY SHEET 6 Educational Obj

ACTIVITY SHEET 6 Educational Objectives: 1) Use the simplified method to determine steady state and Fold here IN THIS EXERCISE YOU WILL HAVE TO SOLVE initial conditions for a capacitive circuit a capacitive circuit using differential equations a capacitive circuit using the General Solution Method FIRST ORDER DIFFERENTIAL EONS AGAIN 2) Calculate the complete solution for current or voltage in Use either the separation of variables method OR the Ptx), ax)method, just like you did for inductors in Lesson 5 3) Calculate the complete solution for current or voltage in t or voltage inOR the Pix), Q) Example 4-7 In the circuit below, find the current and voltage across the capacitor after the switch has been closed. a) Using differential equations b) Using the General Solution Method 10 10 RTH = 10 + (10ay,10) = 15 20 v With the load open-circuited, the current from the source is 2 amps. Therefore, VTH = 20V-( 10)(2A)-10V Thevenin Equivalent Circuit: Solution: 15 First, Thevenize the circuit across the capacitor (consider the capacitor as the load): Io V 10 10 20 V 10 Put the capacitor back including the initial charge, the initial current is (10-2)/15 .533 A, and the (Differential) Loop Equation is: 10-15)--o Put the capacitor back and use KVL to find the integral-differential equation:

Solution

An inductor does not allow sudden changes in current whereas a capicitor does not allow sudden changes in voltage ande hence flux in inductor is stored as current and flux in capicitor is stored as voltage.