Consider a 4M 8 main memory that is built using 512K 8 RAM

Consider a 4M × 8 main memory that is built using 512K × 8 RAM chips

a) How many chips are required?
b) How many address bits are required for each chip?c) How many address bits are required for the entire memory?d) What is the largest unsigned binary number that can be contained in a single word of this
memory? Give your answer in decimal.
e) What is the largest positive 2’s complement number that can be contained in a singleword of this memory? Give your answer in decimal.
f) Configure the 512K × 8 RAM chips to form 4M 8-bit words using high order interleaving (block diagram).
g) Now assume the memory is 4M x 16. Configure eight 1M× 8 RAM chips to form 4M 16-bitwords using high order interleaving (block diagram).

Solution

a)Number of chips are required= (4M*8)/(512K*8)=8 chips.

b)Address bits required for each chip=512k addresses=2⁹⁺¹⁰ =19 address bits

c)address bits required for the entire memory=4M*8=2²⁺²⁰⁺³ =2²⁵ address bits

d)The largest unsigned binary number that can be contained in a single word of this memory=one word is of 8 bits so largest unsigned number=2⁸-1=256-1=255