Convert the equation given below in rectangular coordinates

Convert the equation given below in rectangular coordinates into an equation in polar coordinates: (x 4)^2 + y^2= 16

Solution

(x-4)2+y2=16

The relationship between rectangular coordinates and polar coordinates are

x2+ y2=R2 and x=R cos theta y= Rsin theta

(x-4)2+ y2=16

x2+16-8y+y2=16

x2+y2-8y=0

R2-8Rcos theta=0

R(R-8cos theta)=0

R-8cos theta=0

R=8cos theta

Convert the equation given below in rectangular coordinates into an equation in polar coordinates: (x 4)^2 + y^2= 16Solution(x-4)2+y2=16 The relationship betwee

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