If necessary consult a list of formulas Value of 4 010 5 015

(If necessary, consult a list of formulas.)

Value \"\" of \"Let \"\"
4 0.10
5 0.15
6 0.05
7 0.30
8 0.25
9 0.15

Solution

Using this table,

x   P(x)   x P(x)   x^2 P(x)
4   0.1   0.4   1.6
5   0.15   0.75   3.75
6   0.05   0.3   1.8
7   0.3   2.1   14.7
8   0.25   2   16
9   0.15   1.35   12.15
          
Total       6.9   50

And that

E(x) = Sum(xP(x)),

E(x) = 6.9 [answer]
************

Var(x) = E(x^2) - E(X)^2

As E(x^2) = 50,

Var(x) = 50 - 6.9^2 = 2.39 [ANSWER]

(If necessary, consult a list of formulas.) Value of 4 0.10 5 0.15 6 0.05 7 0.30 8 0.25 9 0.15 SolutionUsing this table, x P(x) x P(x) x^2 P(x) 4 0.1 0.4 1.6 5

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