A dominant gene A governs the production of purple anthocyan
Solution
If these genes are showing mendilian inheritance, the test cross ration shoud be in 1:1:1:1 ratio.
Chisquare analysis
Null hypothesis : The observed values are not deviating from the 1:1:1:1 ratio
Category
purple hairy
purple hairless
green hariless
green hairy
Total
Observed values
73
12
75
9
169
Exptected Ratio
1
1
1
1
4
Exprected Values
42.25
42.25
42.25
42.25
Deviation
30.75
-30.25
32.75
-33.25
D^2
945.5625
915.0625
1072.563
1105.563
D^2/E
22.38018
21.65828
25.38609
26.16716
95.59172
X^2
95.59172
Degrees of freedom
4-1 = 3
Inference: The calculated chi square value is greater than the table value i.e. 7.82 at 3 DF and 0.05 probability. Hence Null hypothesis is rejected. Those genes are not showing mendilian inheritance which means those are not showing indipendent assortment.
| Category | purple hairy | purple hairless | green hariless | green hairy | Total |
| Observed values | 73 | 12 | 75 | 9 | 169 |
| Exptected Ratio | 1 | 1 | 1 | 1 | 4 |
| Exprected Values | 42.25 | 42.25 | 42.25 | 42.25 | |
| Deviation | 30.75 | -30.25 | 32.75 | -33.25 | |
| D^2 | 945.5625 | 915.0625 | 1072.563 | 1105.563 | |
| D^2/E | 22.38018 | 21.65828 | 25.38609 | 26.16716 | 95.59172 |
| X^2 | 95.59172 | ||||
| Degrees of freedom | 4-1 = 3 |

