Write a method called removeInRange that accepts three param

Write a method called removeInRange that accepts three parameters, an ArrayList of Strings, a beginning

String, and an ending String, and removes from the list any Strings that fall alphabetically between the start

and end Strings. For example, if the method is passed a list containing the elements (“to”, “be”, “or”, “not”, “to”,

“be”, “that”, “is”, “the”, “question”), “free” as the start String, and “rich” as the end String, the list\'s elements

should be changed to (“to”, “be”, “to”, “be”, “that”, “the”). The “or”, “not”, “is”, and “question” should be removed

because they occur alphabetically between “free” and “rich”. You may assume that the start String alphabetically

precedes the ending String.

Solution

public static void removeInRange(ArrayList<String> a,String startString,String endString)
{
for(String a1 : a) {
if(a1.compareTo(startString)>0 && a1.compareTo(endString)<0)
a.remove(a1);
}
  
for(String a1:a)
{
System.out.print(a1 + \" \");
}
}