If the force is strong enough to cause slipping which of the

If the force is strong enough to cause slipping, which of the following will occur to the black test bar as a result of slippage on slip planes?

Solution

solution:

1)here BCC means body centered cubic crystal has more ductile nature due to availability of more slip plane in slip system

2) but here force applied is enough to cause deformation by slip which is plastic type deformation hence slip planes would not return to there original position

3) direction in which slip occure is called slip direction and plane is known as slip plane

4) here by schmid\'s law tension is ressolve in to two component in plane of crystal along slip direction and perpendicular to slip direction and it is acting as shear stress and cause deformation of component

4) here if angle made by plane are m and n with respect to tension axis and normal to tension axis then critical ressolve shear stress is given as if force is F

CRSS=F(cosm.cosn)

and where energy for dislocation is

E=KLGb2

K=constant

l=dislocation length

G=modulus of elasticity

b=berger vector

5) here in given problem both angle for both plane is m=n=45 and dislocation length is same hence energy is same ,hence slip will be along both the direction with equal magnitude

6) as slip is permanent in both direction it leads to elongation of bar hence bar will be longer at end

7) but as slip plane are not located cenral along tension axis and due to offset present bar will start reducing diameter from one end where slip planes are closure to surface

8) hence finally bar will permanently long with necking dominent at one surface only