Find the phase shift of the function y 5 sin2x pi2 5pi uni

Find the phase shift of the function y = -5 sin(2x - pi/2) 5pi units up pi/4 units to the right 2pi units down pi/2 units to the left Give the amplitude or period as requested period of y =cos 5x 1 5 2pi/5 2pi Find the phase shift of the function y = -3 cos(1/4x + pi/4) pi/16 units to the right pi/4 units to the left pi units to the left 3pi units to the right Use an identity to write the expression as a single trigonometric function or as a single number. sin 72 degree/1-cos 72 degree Use a sum or difference identity to find the exact value tan 75 degree Perform the indicated operations and simplify the result so there are no quotients sin theta/cos theta + cos theta/sin theta

Solution

1) given y = -5 sin(2x - pi/2)

for phase shift

2x -pi/2=0

2x =pi/2

x =pi/4

so phase shift is pi/4 units to right ( positive sign)

So OPTION B)

2).

Y= cos5x

amplitude =1

and

period of cosx =2pi

5x =2pi

x =2pi/5

so period of Y is \'2pi/5\'

3).

Y =-3 cos(1/4x +pi/4)

so 1/4x +pi/4=0

1/4x =-pi/4

x=-pi

pahse shift is pi to the left hand side

post other three in different question