A car is driving a distance of 10 miles The chart below give

A car is driving a distance of 10 miles. The chart below gives the distance the car has traveled at several times during the trip. Calculate the average rate of change between each successive pair of times. What is the common name for this value? Time (min)0 5 8 12 18 20 Distance (miles) 0 2 4 6 8 10

Solution

(0,5) :
We just do (difference in distance)/(difference in time)
= (2 - 0) / (5 - 0)
2/5 miles/min
= 0.4 miles/min

(5,8) :
(4-2)/(8-5)
= 2/3 miles/min

(8,12) :
= (6-4)/(12-8)
= 2/4
= 0.5 miles/min

(12,18):
= (8-6)/(18-12)
= 2/6
= 1/3 miles/min

(18,20) :
= (10-8)/(20-18)
= 2/2
= 1 mile/min

These are the average rates...

The common name is \"average velocity\"