Find the standard form of the equation of the circle with th

Find the standard form of the equation of the circle with the given characteristics. Center: (5, -1); point on circle: (1, -3) (x - 5)^2 + (y +-l)^2 =32

Solution

given centre =(5,-1) , point on circle =(1,-3)

[(x-5)²+(y-(-1))²] =[(1-5)²+(-3-(-1))²]

[(x-5)²+(y-(-1))²] =[16+4]

[(x-5)²+(y-(-1))²] =20

(x-5)²+(y-(-1))² =(20)²

(x-5)²+(y+1)² =20 is standard form of circle