Find the angle between the vectors 9 8 and 8 6 Carry your in

Find the angle between the vectors (9, 8) and (-8, 6). Carry your intermediate computations to at least 4 decimal places. Round your final answer to the nearest degree.

Solution

vectors are (9,8) and (-8,6)

Let u= (9,8)   and v=(-8,6)

u.v= 9*-8 + 8*6= -24

I u I= sqrt(9^2 + 8^2) = sqrt 145=12.0416

I v I=sqrt(-8^2 + 6^2)=10

cos theta=u.v/(I u I I v I)

cos theta=-24/(10*12.0416)

theta=101 degree