A vitual memory system with 32 bit address space uses a two

A vitual memory system with 32 bit address space uses a two level page table. The First level page leve table has 1024 entries. What is the total size of the page tables for a page size of a) 1K b) 1 M 4.

A virtual memory system with 32 bit address space uses combined segementation and paging supporting upto 4 segments. How many page table entries per segment are required if the page size if a) 1 K b ) 1 M

Solution

Total page table size-

a. Page size= 1k = 2¹⁰

page table size=page size*total entries in page table

=2¹⁰ * 2¹⁰

  =1MB

b.Page size= 1M= 2²⁰

page table size=page size*total entries in page table

=2²⁰ * 2¹⁰

  =1GB