True False Assume you have a normal distribution representin
True
False
| Assume you have a normal distribution representing the likelihood of completion times. The mean of this distribution is 12, and the standard deviation is 5. The probability of completing the project in 8 or fewer days is the same as the probability of completing the project in 18 days or more. |
Solution
It is given that mu=12, sigma=5
X=8, convert the X value into z score:
Z=(X-mu)/sigma=(8-12)/5
=-0.8
Now, P(x<8)=P(Z<-0.8)
=0.2119
X=18, thus,
Z=(X-mu)/sigma=(18-12)/5
=0.6
Now, P(x>18)=P(Z>0.6)=0.7257.
Thus, the statement is false.
