Prove that if a b c and d arc integers such that a b c d
Prove that if a, b, c and d arc integers such that a + b = c + d, then the matrix A = [a b c d] has integer eigenvalues.
Solution
A = ( a b , c d)
A- xI = ( a -x b , c d-x)
Charactereistice polynomial: (a-x)(d-x) - bc =0
ad -x(a+d) +x^2 -bc =0
x^2 -x (a+d) + ad -bc =0
As a + b = c + d then so a + d = (c + d - b) + d = (c + d) + (d - b) and ad - bc = (c + d - b) d - bc = cd + d^2 - bd - bc = d(c + d) - b (c + d) = (c + d)(d - b)
Quadratic function can be written as :
x^2 - [(c + d) + (d - b)] x + (c + d)(d - b) =0
factorised = (x - (c + d)) (x - (d - b))
Roots are c + d and d - b as given a + b = c + d, are the same things as a + b, and a - c
(subtract c + b from both sides of the equality a + b = c + d you find that a - c = d - b.)
As a, b, c, d are integers , so the eigen values are integers
![Prove that if a, b, c and d arc integers such that a + b = c + d, then the matrix A = [a b c d] has integer eigenvalues.SolutionA = ( a b , c d) A- xI = ( a -x Prove that if a, b, c and d arc integers such that a + b = c + d, then the matrix A = [a b c d] has integer eigenvalues.SolutionA = ( a b , c d) A- xI = ( a -x](/WebImages/14/prove-that-if-a-b-c-and-d-arc-integers-such-that-a-b-c-d-1018387-1761526444-0.webp)