The delivery times for all food orders at a fast food restau
The delivery times for all food orders at a fast food restaurant during lunch hour are normally distributed with a mean of 6.7 minutes and a standard deviation of 2.1 minutes. Find the probability that the mean delivery time for a random sample of 16 such orders at this restaurant is between 7 and 8 minutes.
Solution
We first get the z score for the two values. As z = (x - u) sqrt(n) / s, then as
x1 = lower bound = 7
x2 = upper bound = 8
u = mean = 6.7
n = sample size = 16
s = standard deviation = 2.1
Thus, the two z scores are
z1 = lower z score = (x1 - u) * sqrt(n) / s = 0.571428571
z2 = upper z score = (x2 - u) * sqrt(n) / s = 2.476190476
Using table/technology, the left tailed areas between these z scores is
P(z < z1) = 0.716145417
P(z < z2) = 0.993360364
Thus, the area between them, by subtracting these areas, is
P(z1 < z < z2) = 0.277214948 [ANSWER]
