Table for a standard normal distribution of z z0 z1 z128 z16

Table for a standard normal distribution of z

z=0

z=1

z=1.28

z=1.645

z=1.96

z=2.33

P(Z<=0)=0.5

P(Z<=1)=0.84

P(Z<=1.28)=0.9

P(Z<=1.645)=0.95

P(Z<=1.96)=0.975

P(Z<=2.33)=0.99

Given above table, the probability P(Z>=2.33) is

Solution

P( Z >2.33) = 1 - P(Z < 2.33)

P( Z> 2.33 ) = 1-0.99

P( Z > 2.33) = 0.01