Prove by Induction 1 2n n3 for all n 2SolutionPn 12n n3

Prove by Induction:

1 + 2n < n3 for all n >= 2

Solution

P(n); 1+2n < n3 , n>=2

Basic Step :

Put n =2,

L.H.S,

1+2(n) = 1+4=5

R.H.S.

n3=8

5<8

Hence Proved,

Now Let us assume that P(k) is true and we can prove that P(k+1) is also true,

P(k): 1+2(k)<k3.....................(1)

P(k+1): 1+2(k+1)<(k+1)3

1+2k+2< k3+1+3k2+3k

k3>1+3k2+3k

and We know that k<k2, 1<k

So, we can write it as in in this form

3k2+3k+1< 3(k2)+3(k2)+1(k2)

7k2<k3

So, we can write it as

1+2(k+1)<(k+1)3

Hence,

By the principal of mathematical induction P(k+1) is true for all numbers greater than or equal to 2.

Prove by Induction: 1 + 2n < n3 for all n >= 2SolutionP(n); 1+2n < n3 , n>=2 Basic Step : Put n =2, L.H.S, 1+2(n) = 1+4=5 R.H.S. n3=8 5<8 Hence P

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