prob 5 Random variables X and Y have joint PDF given by 10 S
prob
Solution
E[X+Y] =integral(0->1)integral(0->1) (x+y)3y dxdy
=integral(0->1)integral(0->1) (xy+3y^2) dxdy
=integral(0->1) (0->1) (xy^2/2+y^3) dx
=integral(0->1) (x/2+1) dx
= (0->1) x^2/4 +x
= 1/4 +1
= 5/4 Answer
E[X] =integral(0->1)integral(0->1) (x)3y dxdy
=integral(0->1)integral(0->1) (3xy) dxdy
=integral(0->1) (0->1) (3xy^2/2) dx
=integral(0->1) (3x/2) dx
= (0->1) 3x^2/4
= 3/4 Answer
E[Y] =integral(0->1)integral(0->1) (y)3y dxdy
=integral(0->1)integral(0->1) (3y^2) dxdy
=integral(0->1) (0->1) (y^3) dx
=integral(0->1) (1) dx
= (0->1) x
= 1 Answer
P(A) =integral(0->1)integral(0->x) 3y dxdy
=integral(0->1)integral(0->x) (3y^2) dxdy
=integral(0->1) (0->x) (y^3) dx
=integral(0->1) (x^3) dx
= (0->1) x^4/4
= 1/4 Answer
= 5/4 Answer
