Compute the probability of each of the following events Roun

Compute the probability of each of the following events:

Round your answers to at least two decimal places.

P(A)=

P(B)=

when we roll the die two times the outcomes will be

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

and so on

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

so totally there will be 36 posiible ways we can get when a die is rolled twice

A is event sum greater than 7

the possibilities are (2,6) (3,5) (3,6) (4,4) (4,5) (4,6) (5,3) (5,4) (5,5) (5,6) (6,2) (6,3) (6,4) (6,5) (6,6)

so there are 15 chances

so P(A) = 15/ 36 = 5/12

B is an event of sum is an odd number

(1,2) (1,4) (1,6) (2,1) (2,3) (2,5) (3,2) (3,4) (3,6) (4,1) (4,3) (4,5) (5,2) (5,4) (5,6) (6,1) (6,3) (6,5)

so there are 18 possible ways of getting sum as odd out of 36 ways

P(B) = 18/36 = 1/2