Let X be a random variable with support 2 1 a where a is a r
Let X be a random variable with support {?2, 1, a}, where a is a real number, P(X = ?2) = 1/2, P(X = 1) = 1/3,
and E(X) = 0.
Find the value of a.
Solution
sum of probability of random variable is one.
P(x=a)+P(x=-2)+P(x=1)=1
P(x=a) = 1 - ( P(x=-2)+P(x=1) )
=1 - (0.5+1/3)
P(x=a) = 0.167
E(x) = a*P(x=a) - 2*P(x=-2) + 1*P(x=1)
=>a*0.167 - 2*0.5 + 1/3 = 0
a = (2*0.5 - 1/3)/0.167
= 3.999
=4.
