solve the following systems of equations xy 6 5x 5z 40 5y z

solve the following systems of equations

x-y = 6

5x -5z= 40

5y+ z= 10

given x-y=6

5x -5z =40=> x-z =8

5y +z =10

add x-z =8,5y +z =10

x-z +5y +z =8+10

x+5y=18

solve x+5y =18, x-y =6

x+5y -x+y =18-6

6y =12

y=2

solve x-y =6 , y =2

x-2=6

x=8

solve x=8 , x-z=8

8-z =8

z=0

solution is x =8 ,y=2,z=0