7 If a discrete random variable X has the following probabil
7. If a discrete random variable X has the following probability distribution:
X -2 - 1 0 1 2
P(X) 0.2 0.3 0.15 0.2 0.15
Use this to find the following:
(a) The mean of X and E[X^2].
(b) The probability distribution for Y = 2X^2 + 2 (i.e, all values of Y and P(Y )).
(c) Using part (b) (i.e, the probability distribution forY ), find E[Y ].
(d) Using part (a), verify your answer in part (c) for E[Y ].
Solution
E(X) =-0.2
E(X2) =1.9
(b) The probability distribution for Y = 2X^2 + 2
E(Y) = 5.8 using pdf
E(Y) =E(2x^2+2) = 2E(X^2)+2 = 3.8+2
=5.8
verified
| Total | ||||||
| x | -2 | -1 | 0 | 1 | 2 | |
| p | 0.2 | 0.3 | 0.15 | 0.2 | 0.15 | 1 |
| xp | -0.4 | -0.3 | 0 | 0.2 | 0.3 | -0.2 |
| x^2p | 0.8 | 0.3 | 0 | 0.2 | 0.6 | 1.9 |
