Suppose X has a continuous uniform distribution over the int

Suppose X has a continuous uniform distribution over the interval [-1, 1]. Determine the mean and variance of X. Mean= (Round the answer to 3 decimal places.) Variance=

Solution

PDF of Uniform Distribution f(x) = 1 / ( b - a ) for a < x < b
b = Maximum Value
a = Minimum Value
Mean = a + b / 2
Standard Deviation = Sqrt ( ( b - a ) ^ 2 / 12 )

a)
Mean = a + b / 2 = 0
b)
Standard Deviation = Sqrt ( ( b - a ) ^ 2 / 12 ) = 0.577